The latest Numberphile video reveals a number I had never heard of - Mills' Constant.

It by plugging it into a simple equation, it generates an infinite number prime numbers.

But there's a catch:

After posting the video, a lot of people asked for the proof.

Dr James Grime - who stars in the video - has since sent me a link to the proof.

HERE IT IS.

Want more prime number videos? Here is our prime playlist.

## Friday, 19 July 2013

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I would like to ask a few questions regarding the proof that we are given.

ReplyDelete1. Why does this proof depend on the Riemann's Hypothesis?

2. In (4) and (5), why is P_(n+1)^(3-n-1) greater than P_n^(3-n)? In addition, why is [P_(n+1)+1]^(3-n-1) smaller than [P_n+1]^(3-n)?

3. Why does it follow, in the end of the proof, that A<v_n?

I apologize if the answer seems to be trivial. Please answer my questions. Many thanks.

I found a flaw in this proof.

ReplyDelete(4) states that for all non-negative integer n, P_(n+1)^(3-n-1) > P_n^(3-n).

However, when n=3,

P_(n+1)^(3-n-1)

=P_(3+1)^(3-3-1)

=P_4^(-1)

<1

=P_3^0

=P_3^(3-3)

=P_n^(3-n)

Therefore (4) in the proof is wrong, thus the whole proof is wrong.

This comment has been removed by the author.

DeleteThis comment has been removed by the author.

DeleteThis is only true for n less than or equal to three. But it is true for all n greater than 3, so you can still confirm (by taking the limit as n goes to infinity) that it is a bounded sequence, which was the point of showing that it is a decreasing function.

DeleteBasically it says some nth prime to some power x is less than the next prime in the sequence raised to one less power than x. Which is true of the sequence in 2). This paper has been published in one of the largest mathematical journals for over 60 years, I might suggest holding back a little bit on thinking you've disproving it next time!

DeleteI believe the the comments referring to a flaw are a due to a typesetting problem with the proof (.pdf) that was linked. The proof shows terms like P_(n+1)^(3-n-1) where it should really be P_(n+1)^3^(-n-1).

ReplyDeleteIt looks like every place where the exponent 3-n is used, it should read 3^-n, and every place where the exponent 3-n-1 is used it should read 3^-n-1.

Of course, it's late and I could be wrong

thank you

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